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Some researchers believe that the reproduction of multichannel spatial audio would be improved by using separate transducers for the direct and diffuse components of the sound. This research seeks to empirically test this assumption. The perceptual effect of angular separation in commonly used 5.0 and 7.0 multichannel systems was investigated. Four listening experiments were performed involving several schemes of separation and a variety of experimental conditions. The listeners consistently preferred schemes with separation. The perceptual effects of four types of management of direct and reflected parts of spatial impulse responses (SIR) were considered: using complete SIRs in all channels; removing the direct sound (DS) from all but the center channel in a standard 5.0 system; removing ambience from the center channel in a standard 5.0 system; applying both of the above operations (separating DS from reflected sounds RS in particular channels). Depending on the configuration, separation did in fact have advantages.
Authors:
Kleczkowski, Piotr; Krol, Aleksandra; Malecki, Pawel
Affiliation:
Department of Mechanics and Vibroacoustics, Audio Engineering Group, AGH University of Science and Technology, Krakow, Poland
JAES Volume 63 Issue 6 pp. 427-442; June 2015
Publication Date:
June 30, 2015
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Philip Newell |
Comment posted September 4, 2015 @ 19:06:31 UTC
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On page 433 of the June edition of the AES Journal, in a paper called 'Improved Multichannel Sound Reproduction Quality', it says, 'The room met most of the ITU-R [BS.1116] criteria or has parameters very close to recommended. It meets the criteria for floor area and the ratio of dimensions. The RT is much shorter than the recommended 0.56 s.' On the previous page (432), the authors gave the size of their room as about 75 m3, with a floor area of about 26 m2 [3.9 m x 6.7 m x 2.8 m]. (Respond to this comment)
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Author Response Piotr Kleczkowski |
Comment posted November 5, 2015 @ 17:30:57 UTC
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Philip, We appreciate your comment. We are sorry for this mistake. The BS.1116 recommends that: Tm = 0.25(V/V0)^1/3, where V is the volume of the room and V0 is the volume of the reference room (100 m3). In our case this makes Tm = 0.23 s, very close to your assessment. Our measured RT20 was 0.15 s and we stated that in the paper, which I hope reduces the meaning of our mistake. Best regards, Piotr
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Philip Newell |
Comment posted November 7, 2015 @ 16:32:39 UTC
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Dear Piotr, OK; thank you for the clarification.
Best wishes,
Philip |
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